Sähköä tuulella pisaroista

Sähköä tuulella pisaroista

ViestiKirjoittaja Nelikulma » 07.05.2013 21:44

Hollannissa kehitellään "siivetöntä" tuulivoimaa, jossa tuulienergia muutetaan sähköksi vesipisaroiden avulla.
Yksinkertaistaen: suuttimista ruiskutetaan varautuneita pisaroita, jotka tuuli puhaltaa pois sähkökentästä. Siitä virta.

Tämä tuo mieleen hiukan ne tipantiputinlelut, joilla kuivissa olosuhteissa saatiin kerättyä isojakin jännitteitä. Ei silti taida olla ihan samaa periaatetta?

http://www.techthefuture.com/energy/dut ... wer-plant/
Nelikulma
 
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Re: Sähköä tuulella pisaroista

ViestiKirjoittaja jussik5 » 08.05.2013 00:07

Taitaapa olla ;)

"As the wind forces the electrically charged droplets against this electric field towards the earth, the converter is charged to DC voltages of between 80 and 100 kilovolts. After conversion to AC, this can then be used to supply power to the electricity grid. "
"Jos tietäisit 3, 6 ja 9 suuremmoisuuden, sinulla olisi avain universumiin"
Nikola Tesla
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jussik5
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Re: Sähköä tuulella pisaroista

ViestiKirjoittaja esaruoho » 06.09.2013 08:47

ovatkohan nämä jo käytössä? Kelvin Electrostatic Water Dropper /Droplet -hämminkihän on yhäkin hieman kiehtova d-i-y-projekti jota harvemmin ihmiset rakentavat kun Arduino on kiinnostavampi..

Arduino Electrostatic Kelvin Generator? sepäs..
esaruoho
 
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Re: Sähköä tuulella pisaroista

ViestiKirjoittaja siviili2003 » 20.10.2014 19:26

Jonkun ideoita Kelvin experimentistä:

The Kelvin water dropper also works with pure water. This is due to the autoprotolysis of water.
> This means, that due to random collisions between water molecules, it always happens, that there is enough energy that there's a split from 2 H2O -> H3O+ and OH-
> That's why a "neutral" water has a pH of about 7.
> When you now do the Kelvin dropper experiment, then the H3O+ are falling in one container and the OH- in the other container.
> So you have one container with an excess of H3O+, which is now positively charged and another with an excess of OH- which is negatively charged.
> But now let's think about the energy used.
> The energy for splitting the H2O was delivered by the environment!!!
> The energy needed for then separating the two charges was brought up by us, in the case of the Kelvin dropper in the form of gravitational potential energy.
> But the gravitational energy has just been converted to electrical energy. So there was no loss there (sure if we assume a perfect case, with no friction losses, etc)
> So by bringing these charges again nearer to each other, we can get this stored energy electrically back again
> Let's assume we bring them again back until they are as close to each other, as they were when they have been split by the autoprotolysis. So we would have got all energy back, which we needed. But we still have now H3O+ and OH- molecules.
> When we would finally let them merge again, they would generate heat.
> So it would cool at the top of the apparatus but heat at the place of recombination.
> So it acts as a heat pump. But in total we didn't need to input any energy.
> This sure is a theoretical approach. BTW. One could also just discharge the two container to get again electrical energy, plus in one container an excess of O2 and in the other an excess of H2.
> We created H2.
> But we would then have to be aware, that the electrical energy we would get back is not as much as invested for the separation, as there would be a small voltage loss.
> As it needs again energy to make 2H2O + O2 out of 4OH- and 2H20 + H2 out of 2H3O+
> But it doesn't need as much energy as converting it directly out of H20, as the autoprotolysis gave us one energy step.

¤
tuo idea että staattinen varaus vetäisi deuteriumit toiseen purkkiin, ja että veden pH voisi olla erilainen eri alasäiliöissä?
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siviili2003
 
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